4 ms·
It is given that P(A | X) = .99 and P(B | X) = .01, because (by assumption) the first doctor gives you perfect predictions given the information X. Clearly P(A
by gizmo686 10y ago
It is given that P(A | X) = .99 and P(B | X) = .01, because (by assumption) the first doctor gives you perfect predictions given the information X. Clearly P(A or B | X) = 1, so P(C | X) = 0 for any C not in A or B.