3 ms·
I'm not sure I understand either. Any one-to-one function where the name falls under the inverse image of the range works (notably, stupid things like the ident
by LolWolf 10y ago
I'm not sure I understand either. Any one-to-one function where the name falls under the inverse image of the range works (notably, stupid things like the identity mapping along with, you know, binary representations, etc).