2 ms·
x^y/y = z x= chance of a correct answer (1/4) y= number of random attempts 1/4^2 divided by 2 = 1/32 (The odds of picking the correct answer twice in two attem
by joubee 16y ago
x^y/y = z
x= chance of a correct answer (1/4)
y= number of random attempts
1/4^2 divided by 2 = 1/32 (The odds of picking the correct answer twice in two attempts) and so on..... the more you try the less chance you have of succeeding so just give up and cheat off the guy next to you. I made this crap up so what's the chance of it being right? a)0% b)0^ c)what he wrote d)no chance