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Chrome is only free software if you build it from source (http://code.google.com/intl/de/chromium/terms.html http://code.google.com/intl/de/chromium/terms.html)
by vog 16y ago
Chrome is only free software if you build it from source (http://code.google.com/intl/de/chromium/terms.html http://code.google.com/intl/de/chromium/terms.html). If you use their pre-built executable (as most people do), different terms apply (http://www.google.com/chrome/intl/en/eula_text.html http://www.google.com/chrome/intl/en/eula_text.html).
Also, the license isn't everything. It is also important which entity controls the official version of a software. It makes a huge difference whether the decision process is designed for transparency, or whether you can only audit the produced code commits afterwards.
So instead of forking Firefox, it might be a better idea to fork Chrome.
That way, we'd have an independent version that's regularily checked (and fixed) by persons outside of Google. And we could also provide a free binary to which Google's strange terms doesn't apply.
(It would be interesting to see how Google reacts on such a fork. Will they insist on their term and try to apply them to the sources, or will they keep Chrome being free software?)
- Perceval 16y ago>a better idea to fork Chrome. ...an independent version that's regularily checked (and fixed) by persons outside of Google. We already have this. It's called SRWare Iron. http://en.wikipedia.org/wiki/SRWare_Iron http://en.wikipedia.org/wiki/SRWare_Iron
- Jach 16y agoFYI, until recently if you compiled Firefox under Gentoo with +branding (now the message comes up with -bindist): You are enabling official branding. You may not redistribute this build to any users on your network or the internet. Doing so puts yourself into a legal problem with Mozilla Foundation You can disable it by emerging ${PN} _with_ the bindist USE-flag I don't know what those legal problems are (as far as I can tell, it's just the Firefox logo), but I think that's interesting.