4 ms·
I mean you assign the value of the expression to your result. e.g: uint64_t x = 0; ... uint32_t y = (x+=x*x+9)>>32;
by eutectic 10y ago
I mean you assign the value of the expression to your result.
e.g:
uint64_t x = 0;
...
uint32_t y = (x+=x*x+9)>>32;