3 ms·
Not necessarily, it could be e if you're using natural logarithms. Anyway: log10(12.74) = 1.10, log10(80) = 1.90. So, it's a little less than a full order of ma
by carlob 10y ago
Not necessarily, it could be e if you're using natural logarithms. Anyway: log10(12.74) = 1.10, log10(80) = 1.90. So, it's a little less than a full order of magnitude, but pretty close.