2 ms·
No, for example the integral sqrt(1 - x^2) from x = 0 to x = 1. Or any other integral over a circle/sphere for that matter.
by kutkloon7 10y ago
No, for example the integral sqrt(1 - x^2) from x = 0 to x = 1. Or any other integral over a circle/sphere for that matter.
- CJefferson 10y agoNothing wrong with that, it's still a computable number -- I'm not suggesting doing away with all real numbers, just the non-computable ones. I don't claim to have thought through every detail, but having now gone and done some reading, this seems fine in the world of constructivism, which only requires computable numbers (and therefore only countable infinities of numbers)