You couldn't do an odd number of codes, but if you have an odd number of positions, I suppose you could have one position represented by two adjacent codes. So,

You couldn't do an odd number of codes, but if you have an odd number of positions, I suppose you could have one position represented by two adjacent codes. So, you could have a wheel with 5 equal pie slices, but on the reverse, one of those slices is divided in half, with a different encoding on each, that both resolve to the same value/result.