3 ms·

grep -rl 500 . wasn't accepted. Am I wrong or is it wrong?

• leblancfg 10y ago
  You are: grep matches strings, not integers. grep -rl '500' works just fine.
  • tne 10y ago
    There is no concept of an integer on an argument vector. Quoting in bash just escapes IFS characters (usually whitespace) to control whether to include them in a given argument on the vector, but these arguments (as passed to exec) are always character strings (with or without quoting).
  • godelski 10y ago
    Interestingly enough grep -rl "500" . doesn't work because it returns with the "./".
• snuxoll 10y ago
  Only filenames matching access.log should be returned. Unfortunately, since shopt globstar is disabled I ended up needing to do this: grep 500 $(find . -type f -iname "access.log*")
  • JoshTriplett 10y ago
    You could also include "shopt -s globstar; " at the beginning of your line.
  • joshka 10y ago
    grep -r 500 --include access.log
• slavik81 10y ago
  That returns the filenames in the format "./access.log" but it wanted "access.log". It's a bug. I used echo -e 'access.log\naccess.log.1\nREADME'. :D
  • Galanwe 10y ago
    Hahahaha I did the exact same thing
  • coherentpony 10y ago
    Gotcha. Thanks.