3 ms·
So the issue you faced was that you used z twice, and x not at all? In that case, linear types (http://edsko.net/2017/01/08/linearity-in-haskell/ http://edsko.n
by neilparikh 10y ago
So the issue you faced was that you used z twice, and x not at all? In that case, linear types (http://edsko.net/2017/01/08/linearity-in-haskell/ http://edsko.net/2017/01/08/linearity-in-haskell/) may have caught that.
- kazinator 10y agox not being used at all can be caught by a simple unused variable warning. In this situation, the variable's value was used somewhere, so that didn't go off.