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In a two player no-limit hold'em game, a game theory optimal solution will be at a Nash equilibrium. see: https://en.wikipedia.org/wiki/Nash_equilibrium#Nash.2

• xapata 10y ago
  You misunderstood "a solution" to mean the only optimal solution. Also, note that Nash equilibrium assumes the opponent does not change strategy. Once you relax that assumption, especially with the idea that you can induce change, another strategy becomes viable. Check out the "Occurrence" section in the article you linked to.
  • andrewprock 10y ago
    A Nash equilibrium strategy does not assume that an opponents strategy never changes. A Nash equilibrium has the property that if the opponents strategy deviates from a Nash equilibrium, then the opponent will lose.
    • xapata 10y ago
      That's neither my memory of the phrase from school nor my reading of the Wikipedia article. Nash equilibrium may not exist if one of the players follows, say, a Markov switching process. If that process causes the opponent to stop seeking equilibrium or to settle into a false equilibrium, then the switching process may have been a better strategy than seeking equilibrium.