5 ms·
Or you could just say that, for N independently distributed samples, the accuracy improves by a factor of at most sqrt(N) :)
by jessriedel 10y ago
Or you could just say that, for N independently distributed samples, the accuracy improves by a factor of at most sqrt(N) :)
- wolfgke 10y agoThis does only hold if the standard deviation \sigma is the same for all of the normal distributed variables. This is not the case here: Galileo is supposed to be more precise than Navstar-GPS (no surprise, since it is the newer system) - though I know that the US government is working on to increase the precision for Navstar-GPS. On the other hand (source: http://www.navipedia.net/index.php/GLONASS_Performances#GLONASS_Accuracy_Comparison http://www.navipedia.net/index.php/GLONASS_Performances#GLON...) GLONASS is less precise than Navstar-GPS.
- jessriedel 10y agoWell, I said "at most", so it holds for all sigma_i. As you know, when the sigma_i are very different, then the accuracy is approximately given by the best accuracy (smallest sigma_i), so there's very little improvement from averaging.
- wolfgke 10y ago> Well, I said "at most", OK, you are right. This can indeed be shown.