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Are you...joking? Or am I supposed to be taking that explanation as your reasoning behind why that's a lambda? I'm hoping for the former.
by jgg 16y ago
Are you...joking? Or am I supposed to be taking that explanation as your reasoning behind why that's a lambda?
I'm hoping for the former.
- ComputerGuru 16y agoIt was a badly played joke. Yes, it's not a lamda. It's reminiscent of the "goes to" except it doesn't actually change. In this joke C++ post, I guess it most resembles the "limit" operator/function in calculus.
- jgg 16y ago>It was a badly played joke. Ah, apologies then. I vaguely understood what the humor was there, but I wasn't sure if that's what you were going for. (-: