3 ms·
Which doesn't work once the operation is not commutative. Serializing parallel operation is hard!
by maweki 10y ago
Which doesn't work once the operation is not commutative.
Serializing parallel operation is hard!
- throwanem 10y agoVery true. If nothing else, perhaps it's worth choosing an example with which a pedant like me can't quite so trivially quibble!