4 ms·
This is simply incorrect. From a theoretical standpoint, productivity is a volumetric measure (Outputs / Inputs). From a more practical standpoint, even if outp
by spangry 10y ago
This is simply incorrect. From a theoretical standpoint, productivity is a volumetric measure (Outputs / Inputs). From a more practical standpoint, even if output is measured in dollar denominated terms, the methodology used to measure TFP/MFP minimise the effects of inflation on the calculated residual, primarily by:
- also measuring inputs in these terms (e.g. wages paid to labour, rents paid to capital)
- adjusting prices with reference to a selected base-year so that movements in MFP/TFP are comparable across years
And empirically, what has been historically observed is actually the opposite of what you suggest: productivity and inflation are inversely correlated (i.e. periods of high inflation have show low productivity and vice-versa). Here's a paper from some absurd and hubristic mainstream economists on this issue: https://www.rba.gov.au/publications/rdp/2003/pdf/rdp2003-10.pdf https://www.rba.gov.au/publications/rdp/2003/pdf/rdp2003-10....
It's actually even more complicated than just this. But I can't really be bothered to get in to it. But good luck with that Mises Institute stuff.
- RA_Fisher 10y agoI used to "measure" productivity as part of expert witness testimony in U.S public utility rate cases, so I'm not ignorant of the difficulty of doing so (as you expand on). It's precisely that difficulty in calculation that I see as one clue among many that the optimization task the Fed attempts is not better than the market for money.