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Can you explain how you can make a blocking call to an async function without overhead ?
by fooyc 10y ago
Can you explain how you can make a blocking call to an async function without overhead ?
- eridius 10y agoIf you accept that using the async call in an asynchronous nature doesn't have overhead, then you can turn it into a synchronous call by saying something like `.wait()`.
- fooyc 10y ago> If you accept that using the async call in an asynchronous nature doesn't have overhead Obviously that's not the case. There is a lot of overhead.