3 ms·
-log_2 log_2 sqrt(...(sqrt(2))...) {with n copies of sqrt} = -log_2 (2^-n log_2 2) = -log_2 (2^-n) = -(-n) = n. I would say that you need only one 2 if you rep
by lifthrasiir 10y ago
-log_2 log_2 sqrt(...(sqrt(2))...) {with n copies of sqrt} = -log_2 (2^-n log_2 2) = -log_2 (2^-n) = -(-n) = n.
I would say that you need only one 2 if you replace log_2 by lg, so we should make lg taught in high schools... wink