2 ms·
An easy way to try this is to consider any that start with 1+2+3. You can create a second version by replacing this with 1×2×3. For example, 10914 = 1 ×
by Cogito 10y ago
An easy way to try this is to consider any that start with 1+2+3.
You can create a second version by replacing this with 1×2×3.
For example,
10914 = 1 × 2 × 3 × (4^5 + 6 + 789)
10914 = (1 + 2 + 3) × (4^5 + 6 + 789)