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It will if the human is not playing perfectly. Which of course they aren't because they are human. The question is if the computer is playing close enough to eq
by spectrum1234 10y ago
It will if the human is not playing perfectly. Which of course they aren't because they are human. The question is if the computer is playing close enough to equilibrium/optimal compared to the humans.
- xapata 10y ago> equilibrium/optimal That assumes that the Nash equilibrium is optimal. It isn't. Optimal play is to deviate from Nash equilibrium to take the most exploitative strategy against specific opponent weaknesses. This necessarily creates weakness in your own play. Optimal play sends misleading signals to the opponent. Basically, you signal "rock" so that the opponent plays "paper" but you actually play "scissors". (In this metaphor, neither "rock" nor "paper" nor "scissors" are equilibrium strategies.) For example, I might order a couple beers, straddle a few times and start egging on the rest of the players for a round of straddling. To get it going I might throw in a few blind bets. Ask folks to go all-in blind once or twice, for fun. Do that a few times and no one expects you to have a good hand. Well, except for the folks that have seen that story play out before. Except for the beers and bending the rules, the computer can do the same thing.