2 ms·
2017 is the sum of five distinct cubes TWICE OVER: 2017 = 10^3 + 9^3 + 6^3 + 4^3 + 2^3. 2017 = 12^3 + 6^3 + 4^3 + 2^3 + 1^3. As a bonus, it's also the sum of EI
by tpogge 10y ago
2017 is the sum of five distinct cubes TWICE OVER:
2017 = 10^3 + 9^3 + 6^3 + 4^3 + 2^3.
2017 = 12^3 + 6^3 + 4^3 + 2^3 + 1^3.
As a bonus, it's also the sum of EIGHT DISTINCT CUBES:
2017 = 9^3 + 8^3 + 7^3 + 6^3 + 5^3 + 4^3 + 3^3 + 1^3.