No, all moves in rust are memcpy if not optimized out entirely. Rust has affine types so moves don't need to "invalidate" the source value at runtime, the compi

No, all moves in rust are memcpy if not optimized out entirely. Rust has affine types so moves don't need to "invalidate" the source value at runtime, the compiler just doesn't allow you to use the source variable after a move. Rust's answer to copy ctors is Clone, which is always explicitly called. Variable use in rust is a move. Trivially copyable types (Copy) will be copied without compile-time invalidating the old type.