2 ms·
It's really just a nice result of euler's theorem: e^(a * i) = cos(a) + i * sin(a) Where `a` is the angle in radians and `i` is `sqrt(-1)`
by pitaj 10y ago
It's really just a nice result of euler's theorem:
e^(a * i) = cos(a) + i * sin(a)
Where `a` is the angle in radians and `i` is `sqrt(-1)`