5 ms·
You can't have a single virtual particle appearing, it's always two, due to conservation of momentum, charge etc So it'd be a quark-antiquark pair popping up.
by walrus1066 10y ago
You can't have a single virtual particle appearing, it's always two, due to conservation of momentum, charge etc
So it'd be a quark-antiquark pair popping up.
The proton is the lightest Baryon (3 quark particle), there is no lighter Baryon it could decay into. The decay products have to be lighter than the original proton, by at least the mass of the virtual quark pair, to repay the energy 'borrowed' from the vacuum to create the virtual quark pair (because energy is always conserved). So the proton remains unaffected by the virtual particles popping in and out of existence around it. The virtual particles have no choice but to effectively to annihilate with one another and disappear, to pay back the energy debt.
Heavier Baryons (Sigmas, Lambdas) are indeed destabilized by virtual quark pairs, that is the mechanism by which they decay, almost instantaneously, on their own.
You could have an up-anti up quark pair that pops up close to the up quark of the proton, the up quarks could 'swap places', and then the up of the proton annihilates with the anti up of the virtual quark pair, but the the result is still a proton.
- walrus1066 10y agor.e. Heavy baryon decay, here is a feynmann diagram showing a delta baryon decaying into a proton and pion. The down + anti-down quark pair that appears in the middle of the diagram are virtual particles: https://ned.ipac.caltech.edu/level5/Cottingham/Figures/figure1_3.jpeg https://ned.ipac.caltech.edu/level5/Cottingham/Figures/figur...