What if the "stacking" is simply using multiple hash functions in parallel, i.e. not storing one hash but a bunch of hashes all done with different hash functio

What if the "stacking" is simply using multiple hash functions in parallel, i.e. not storing one hash but a bunch of hashes all done with different hash functions? Would that not make finding a collision that works in all hash functions nigh impossible, with the trade-off that you're potentially giving away more information about your input data?