4 ms·
In all examples, `read` and `write` are unsigned, and since they both are the same type, no integer conversions are performed, ergo no overflow. PS. No wrap-ar
by mfukar 10y ago
In all examples, `read` and `write` are unsigned, and since they both are the same type, no integer conversions are performed, ergo no overflow.
PS. No wrap-around either, for different reasons.
- falcolas 10y ago> No wrap-around either, for different reasons. You'll have to explain that to me, since I can't assign `x = 2^32` without wraparound when x is an unsigned 32 bit integer.