4 ms·
If the proof were just that the sum converges to some number 0 <= x <= 1, then you'd be right. But it's showing specifically that the sum lies between the firs
by nilkn 10y ago
If the proof were just that the sum converges to some number 0 <= x <= 1, then you'd be right.
But it's showing specifically that the sum lies between the first term s_0 (which is strictly less than 1) and the sum of the first two terms s_0 - s_1 (which is strictly greater than 0). So there's no possibility for it to converge to a value outside of the interval [s_0-s_1,s_0], which is itself strictly contained inside [0,1].