The expected value of both strategies is to have 1 success, but they have different variance. The first strategy has variance of 0.99, and the second strategy h

The expected value of both strategies is to have 1 success, but they have different variance. The first strategy has variance of 0.99, and the second strategy has variance 0. The chance of n out of 100 hits with the first strategy is: binomial(100,n) x 0.01^n x 0.99^(100-n) edit: asterisks as multiplication signs => italics