4 ms·
Let's assume a psychoactive vodka dose of 10ml and a typical dose of 100ug LSD: Then the respective vodka dose would be 10ml x (320'000ug / 100ug) = 10ml x 320
by blubb-fish 10y ago
Let's assume a psychoactive vodka dose of 10ml and a typical dose of 100ug LSD:
Then the respective vodka dose would be 10ml x (320'000ug / 100ug) = 10ml x 3200 = 32000ml = 32 l
Obviously vodka would be deadly at an amount way below 32l.