4 ms·
If it was base 128 it Would have produced 7 bits. But as it is 122 it produces 6.8 bits, hence a problem.
by beagle3 10y ago
If it was base 128 it
Would have produced 7 bits. But as it is 122 it produces 6.8 bits, hence a problem.
- deckar01 10y ago> This uses one-byte characters encode seven bits and two-byte characters to encode fourteen bits. Hence this attains the goal of encoding seven bits per byte, i.e. the 8 : 7 inflation ratio. The magic is in the 2 byte encoding 110sss1x 10xxxxxx. There are really 890 characters used in this encoding, so it should be called base890. ((2^7)-6)+((6•2)•(2^6))=890