4 ms·
That's not correct. Even though the magnitudes of the value in isolation shrinks, the relative magnitudes are still amplified which is what matters. Consider v
by esrauch 10y ago
That's not correct. Even though the magnitudes of the value in isolation shrinks, the relative magnitudes are still amplified which is what matters.
Consider values 1/2 and 1/4: in the original space it's double but in the squared space it becomes 1/4 and 1/16 so the difference is 4x. Also relevantly if you compare eg 0.9 and 1, the gap between them is amplified after squaring.
- tonyedgecombe 10y agoThose values aren't compared individually, they are summed to calculate the deviation, the result of that sum will be reduced if the values are < 1.