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Huh? No, anyone who writes it in Haskell would not use those lambda abstractions. You would just use "filter isValid (map Person names)".
by wyager 10y ago
Huh? No, anyone who writes it in Haskell would not use those lambda abstractions. You would just use "filter isValid (map Person names)".
- Scriptor 10y agoI'm assuming Person is a record constructor, is isValid here a field in that record or another function?
- prodigal_erik 10y agoHaskell doesn't distinguish the two. If you define Person with named fields including isValid, you automatically get a function named isValid that returns that field, or you can write your own isValid function that examines the whole Person.