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You mean script kiddie scanners. document.getElementById('p').value='5544e312' This isn't going to stop anyone who knows urllib.
by codexon 16y ago
You mean script kiddie scanners.
document.getElementById('p').value='5544e312'
This isn't going to stop anyone who knows urllib.
- zedshaw 16y agoHave you tried using urlib and urllib2? I think that alone prevents anyone from getting to the site. :-) Seriously though, I'm going for simple and if there's a problem then I'll lock it down more completely.
- codexon 16y agoI have written multiple crawlers for sites like facebook with them. import urllib2;urllib2.urlopen("http://learnpythonthehardway.com/login http://learnpythonthehardway.com/login).read() Since you only want basic protection, you could avoid the visual captcha all together and have the "Fill out captcha" button auto-submit.