4 ms·
This proof is nearly equivalent to that proof, but uses the sine function to generate a contradiction. The crucial step involves the fact that: 1 + 2 * product
by blevinstein 10y ago
This proof is nearly equivalent to that proof, but uses the sine function to generate a contradiction. The crucial step involves the fact that:
1 + 2 * product(p', p')
must be divisible by some prime number, where
product(p', p')
is the product of all primes you were talking about.