2 ms·
Questions 8 and 9 remind me of a math YouTube video I saw recently about "weird" infinite series that can sometimes be solved quite easily. IIRC Consider sqrt(
by YZF 10y ago
Questions 8 and 9 remind me of a math YouTube video I saw recently about "weird" infinite series that can sometimes be solved quite easily.
IIRC Consider sqrt(x+sqrt(x +... = x
You need to check the series converges (this can sometimes be tricky but seems the questions tell you they converge). Then you can do this substitution for the infinite piece:
sqrt(x+x) = x
x^2 = 2x
x^2 - 2x = 0
...
y = 1/(1+y)
[IIRC there are situations where a different substitution yields a different result - I don't recall the details]
- YZF 10y agoThis is the video: "Ramanujan's infinite root and its crazy cousins" https://www.youtube.com/watch?v=leFep9yt3JY&t=687s https://www.youtube.com/watch?v=leFep9yt3JY&t=687s