4 ms·
Add 128 to a signed char and the compiler is free to assume it is zero/false (because undefined behavior) OR assume the value is always greater than 127 (becaus
by zlynx 10y ago
Add 128 to a signed char and the compiler is free to assume it is zero/false (because undefined behavior) OR assume the value is always greater than 127 (because undefined behavior). Or if it compiles it into machine code, the result may depend on register width since it may or may not store it back into memory. Resulting in a value either larger than 127 or mod 128 depending on register pressure since the compiler isn't obligated to AND 0xFF because Undefined Behavior.
- qb45 10y ago> Add 128 to a signed char and the compiler is free to assume it is zero/false To be honest, I hope compilers don't do such things. I would vastly prefer to see it run Tower of Hanoi simulation in Emacs at this point. But evading bound-checking of 8bit math done in 32bit registers is totally reasonable (by the standard of usual UB optimizations), thanks.