4 ms·
P(A|B) does not equal P(B|A). The Bayesian fallacy is inappropriately conflating the two. In this case, The commentator confused P(scoring | long possession) an
by benchaney 10y ago
P(A|B) does not equal P(B|A). The Bayesian fallacy is inappropriately conflating the two. In this case, The commentator confused P(scoring | long possession) and P(long possession | scoring). It is very similar to the base rate fallacy to the extent that if someone commits the Bayesian fallacy they almost always also commit the base rate fallacy.