> I mean, how do you put a value into foo so that baz($foo) calls bar? I'm guessing, using foo = 'bar', no? You could, but that makes $foo a string, which is h

> I mean, how do you put a value into foo so that baz($foo) calls bar? I'm guessing, using foo = 'bar', no? You could, but that makes $foo a string, which is horrible. Since PHP has actual function values, it would be much nicer to use them, and hence do: $foo = function($x) { return bar($x); }; This is annoying though, since we're forced to perform an eta-expansion of bar just to avoid the syntax error that `$foo = bar;` gives. It's like writing `0+$n` to avoid getting a syntax error when writing `$n`; completely unnecessary, and most likely a bug in the parser. Unfortunately this isn't always possible either, since it depends on the signature of bar. A more flexible example would be: $foo = function() { return call_user_func_array('bar', func_get_args()); }; This still doesn't preserve things like default arguments though, and we're forced to use a string as a function too (although at least it's encapsulated, so it can't cause us to encounter random 'bar' strings in our context and wonder whether or not they're meant to be strings or functions) :(