Because x86 instructions can cross 4/8/16 byte alignment boundaries, you can't safely set a multi-byte breakpoint in all cases. CPU might execute (bytes [0xCD,

Because x86 instructions can cross 4/8/16 byte alignment boundaries, you can't safely set a multi-byte breakpoint in all cases. CPU might execute (bytes [0xCD, x] -> int x) instruction before the parameter becomes visible and trigger some other exception, whatever happened to be at that address before.