3 ms·
> F_{A->B} = G * M_A * M_B/d(A,B)^3 Your formula is wrong. It's either: F_{a} = F_{b} = G * m_a * m_b/r^2 or \vec{F} = G * m_a * m_b/|r|^3 * {\vec{r
by 4ad 10y ago
> F_{A->B} = G * M_A * M_B/d(A,B)^3
Your formula is wrong. It's either:
F_{a} = F_{b} = G * m_a * m_b/r^2
or
\vec{F} = G * m_a * m_b/|r|^3 * {\vec{r}}
> but where does that come from?
You find that by studying physics, not history of physics.
> it would have been intellectually pleasing(at least for me) to know how Physicists came with it, what's the motivation behind 1/d(A,B)^3, how did people come up with G, how it was measured, etc.
Yes, understanding a specific change in the state of physics at time T is most certainly helped by understanding it at time T-1. But make no mistake here, this is still physics and not history of physics (whatever that means).
- S4M 10y agoThanks for correcting me. The fact that I remembered the formula wrong proves that I didn't understand that formula well enough to remember it. It was been about 13 years since I didn't do any physics, and I forgot most of it, however, I remember well the math I learnt because I understood them much better.
- deleted 10y ago[deleted]