3 ms·
"stuff moving in space at the speed of light, move literally zero on the time axis" No, on a Minkowski diagram with the x axis as a one space-like dimension co
by raattgift 10y ago
"stuff moving in space at the speed of light, move literally zero on the time axis"
No, on a Minkowski diagram with the x axis as a one space-like dimension coordinate (e.g. radius in metres) and the y axis as the time-like coordinate (e.g. -ct, where t is in seconds and c is the speed of light; - because of the sign convention[0]), something travelling at the speed of light traces out a 45 degree angle.[1]
This is a fundamental property of Minkowski spacetime, the spacetime of Special Relativity (and the spacetime in local sections of the fibre bundle in General Relativity).
Indeed, in a hyperbolic solution in General Relativity, everything moves at one second per second on the timelike axis measuring each object's proper time. This is one of many properties of time we do know very well; what's unclear is whether the property is emergent in the behaviour of systems of small objects, or whether it is fundamental to physics and applies to every object everywhere.
General Relativity requires that the manifold be infinitely differentiable, and thus continuous, rather than discrete. Anything that seeks to explain gravitation and the observables from tests of relativity will have tremendous trouble introducing discretization on the background while retaining compatibility with those tests. For all practical purposes, that's true for everything outside the event horizon of a black hole and more recent than the first 1e-38 seconds after the big bang.
[0] https://en.wikipedia.org/wiki/Sign_convention https://en.wikipedia.org/wiki/Sign_convention
[1] https://en.wikipedia.org/wiki/File:Minkowski_diagram_-_photon.svg https://en.wikipedia.org/wiki/File:Minkowski_diagram_-_photo...