3 ms·
There's too much undefined behaviour for even modern C++ to be considered type safe: a dangling reference or invalidated iterator allows you to break it easily,
by dbaupp 10y ago
There's too much undefined behaviour for even modern C++ to be considered type safe: a dangling reference or invalidated iterator allows you to break it easily, accidentally. (Even "opt-out type safety" is a stretch, opt-in-with-extra-tooling-and-tests seems more appropriate.)