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That doesn't address scott_karana's question, as it doesn't speak to the cost of the necessary parts being duplicated in each executable.
by JdeBP 10y ago
That doesn't address scott_karana's question, as it doesn't speak to the cost of the necessary parts being duplicated in each executable.
- mbel 10y agoIt does address the question indirectly. The implicit argument is that the size of duplicated common parts may be lower than size of single instance of everything that is bundled in OpenSSL. There is no proof however if that's the case.