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Swift memory management isn't nearly as expressive as C++ when it comes to references (i.e. unmanaged pointers). You can use in/out/inout parameters on function

Swift memory management isn't nearly as expressive as C++ when it comes to references (i.e. unmanaged pointers). You can use in/out/inout parameters on functions and that's about it. I agree with the parent that Swift memory management is basically like Go or Java: everything is GC'd (reference counting being a form of GC).

hellofunk 10y ago
You don't need in/out params to get references; in Swift, anything defined with "class" is always passed by reference.
- pcwalton 10y ago
  Unmanaged references. Regular old class references aren't unmanaged (they adjust reference counts).