3 ms·

But Iterator's next() returns an Option, not a Result.

• catnaroek 10y ago
  I don't see why you'd want to manipulate iterators by hand, unless you're implementing custom iterators. But, in any case: try!(iter.next().ok_or("end of sequence")) EDIT: Sorry. I was just being dense.
  • glandium 10y ago
    Check out the code that goes along the "no try! for Option" comment in the OP: it is implementing a custom iterator.
    • catnaroek 10y ago
      Oh, my bad. I guess `try!` isn't a good enough replacement for properly treating `Option` and `Result` as monads.