4 ms·
Same in javascript: var fns=[]; for (var i=0; i<3; i++) { fns.push(function(){return i}); }; fns.map(function(x) { return x.call(); });
by loevborg 10y ago
Same in javascript:
var fns=[];
for (var i=0; i<3; i++) {
fns.push(function(){return i});
};
fns.map(function(x) { return x.call(); });
Returns
[ 3, 3, 3 ]