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Aeson/Haskell doesn't require decoding json into user-defined data types. It supports the scenario of turning the data into a plain Map (clojure style) as well
by platz 10y ago
Aeson/Haskell doesn't require decoding json into user-defined data types. It supports the scenario of turning the data into a plain Map (clojure style) as well. The plain Map style is simply a less preferred paradigm in haskell, but its very easy to support this. Getting a map out from your json is a one liner.