4 ms·
I had originally heuristically reasoned in a similar but opposite way, to the wrong answer. To wit: 1. P_{1/6} = 1/6 [when rolling one die, you have a 1/6 chan
by Chinjut 10y ago
I had originally heuristically reasoned in a similar but opposite way, to the wrong answer. To wit:
1. P_{1/6} = 1/6 [when rolling one die, you have a 1/6 chance of getting more than 1/6 many sixes]
2. P_n -> 1/2 as n -> infinity, by the central limit theorem
3. I couldn't see any reason that P_n shouldn't be strictly monotonic.
Thus I expected that P_1 < P_2 < P_3
- thomasahle 10y agoIf you calculated P_1 = 0.665 I suppose you would guess P_2 would be between that and P_infty = 1/2, thus smaller than P_1.