3 ms·
This is not the best wording, but it's what I have for now: Label the top, left, bottom, and right edges of the square T, L, B, and R, respectively (so T and L
by Chinjut 10y ago
This is not the best wording, but it's what I have for now: Label the top, left, bottom, and right edges of the square T, L, B, and R, respectively (so T and L are the ones which must be glued to each other, in suitable fashion). Cut the square down the \ diagonal; this produces two pieces: an L\B triangle and a T\R triangle. Mark the \ sides of these pieces as having to be ultimately glued to each other in the appropriate fashion, and now re-attach them in the way in which L and T are already indicated to be glued (in the process, flipping one of them over). Now one has the equivalent of the M diagram from before, and thus a Mobius strip.
- nobriot 10y agoI also find a Mobius strip, I made the same reasoning
- jsprogrammer 10y agoI believe the bottom of L (BL) must coincide with the left of T (LT) and the top of L (TL) must coincide with the right of T (RT); however, musn't all four points coincide in order to properly reglue the \ diagonal? Wouldn't this appear as a "crimped Möbius strip" (if it is even possible)?