3 ms·
Proving that identity isn't needed here is easy: if the function is only used in a first-order way (ie, it's always called) then the identity can't possibly mat
by samth 10y ago
Proving that identity isn't needed here is easy: if the function is only used in a first-order way (ie, it's always called) then the identity can't possibly matter. That should work in most cases that matter.
- pizlonator 10y agoYou're right, it's easy in strict mode. I hadn't realized this before! In sloppy mode, there's function.arguments. You can walk the stack to find the damned function instance.
- samth 10y agoIn that case, the only identity has to come via function.arguments. Could you therefore allocate the identity lazily, since there's nothing else to compare to?
- pizlonator 10y agoYes, you could. I want to implement this eventually.