3 ms·
I don't think so, at least I can't figure out what would correspond to the expectation step. It seems to be a gradient ascent on a smoothed density function, s
by contravariant 10y ago
I don't think so, at least I can't figure out what would correspond to the expectation step.
It seems to be a gradient ascent on a smoothed density function, so there's only a maximization step, no expectation step is involved.